求x趋于0时,(e^x^2-x^2-1)/x^2(e^x^2-1)的极限

Answer 1

=(e^x^2-x^2-1)/(x^2)·(x^2)
=(e^x^2-x^2-1)/(x^4)
=(2xe^x^2-2x)/(4x^3) 洛比达法则
=(e^x^2 -1 )/(2x^2)
=(x^2)/(2x^2)
=1/2