任意角的三角函数计算。。。

Answer 1

解：（1）原式=cos((24π+π)/3)+tan((-16π+π)/4)
=cos(8π+π/3)+tan(-4π+π/4)
=cos(π/3)+tan(π/4)
=1/2+1
=3/2；
（2）原式=sin(720°+90°)+tan(720°+45°)-cos(360°+0°)
=sin(90°)+tan(45°)-cos(0°)
=1+1-1
=1。

Answer 2

（1）原式=cos(π/3)+tan(π/4)
=1/2+1
=3/2.
(2)原式=sin90°+tan45°-cos0°
=1+1-1
=1.