第1个回答 推荐于2016-02-12
∫[x/(x+1)^2-2]dx
=∫[(x+1-1)/(x+1)^2-2]dx
=∫[1/(x+1)-1/(x+1)^2-2]dx
=ln|x+1|+1/(x+1)-2x+C本回答被提问者采纳
=∫[(x+1-1)/(x+1)^2-2]dx
=∫[1/(x+1)-1/(x+1)^2-2]dx
=ln|x+1|+1/(x+1)-2x+C本回答被提问者采纳
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