第3个回答 2013-01-04
(1)lim(x-->0)sinx/(6x)=1/6lim(x-->0)sinx/x=1/6
(2)lim(x-->0)(1-2x)^(1/x)=lim(x-->0){[1+(-2x)]^(-1/2x)}^(-2)=e^(-2)=1/e^2
(3)原式=-1/2∫(1-x^2)^(1/2)d(1-x^2)=-1/3(1-x^2)^(3/2)+C
(4)令x=sect 则dx=sect*tant*dt
原式=∫sect*tant*dt/tant==∫sectdt==∫[secttant+sec^2(t)]dt/(sect+tant)=ln|sect+tant|+C
=ln|x+√(x^2-1)|+C本回答被提问者和网友采纳