可以再问你一道吗?
A=2x^3-xyz
B= y^3-z^2+xyz
C=-x^3+2y^2-xyz
(x+1)^2+|y-1|+|z| =0
=>
x=-1 and y =1 and z=0
A=2x^3-xyz =-2
B= y^3-z^2+xyz = 1
C=-x^3+2y^2-xyz = 1+2 =3
A-[2B-3(C-A) ]
=-2-[2 -3(3+2)]
=-2-[2 -15]
=9
最后等于11
?
追答A-[2B-3(C-A) ]
=-2-[2 -3(3+2)]
=-2-[2 -15]
=11